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Home/ Questions/Q 6783567
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T16:52:47+00:00 2026-05-26T16:52:47+00:00

A simple comparison of two double values in Java creates some problems. Let’s consider

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A simple comparison of two double values in Java creates some problems. Let’s consider the following simple code snippet in Java.

package doublecomparision;

final public class DoubleComparision 
{
    public static void main(String[] args) 
    {
        double a = 1.000001;
        double b = 0.000001;

        System.out.println("\n"+((a-b)==1.0));
    }
}

The above code appears to return true, the evaluation of the expression ((a-b)==1.0) but it doesn’t. It returns false instead because the evaluation of this expression is 0.9999999999999999 which was actually expected to be 1.0 which is not equal to 1.0 hence, the condition evaluates to boolean false. What is the best and suggested way to overcome such a situation?

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  1. Editorial Team
    Editorial Team
    2026-05-26T16:52:48+00:00Added an answer on May 26, 2026 at 4:52 pm

    Basically you shouldn’t do exact comparisons, you should do something like this:

    double a = 1.000001;
    double b = 0.000001;
    double c = a-b;
    if (Math.abs(c-1.0) <= 0.000001) {...}
    
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