Question

A small bit of code will explain why I’m asking and why this is not a duplicate. (I hope)

>>> def foo():
...    return 1
... 
>>> bar=foo
>>> bar.__name__
'foo'

How do I get ‘bar’?

I’ve tried inspect and frames, but everything I’ve found so far fails this test.

Answer 1

bar is just a reference to an already created object(foo), doing bar=foo means you created another reference to the same object.

In [62]: def foo():pass

In [63]: bar=foo

In [64]: spam=bar     #another reference to foo function object

In [65]: spam.__name__,bar.__name__
Out[65]: ('foo', 'foo')

In [66]: spam is foo,bar is foo
Out[66]: (True, True)

In [67]: import sys

In [68]: sys.getrefcount(foo)  # no of variable pointing to that object

Out[68]: 4           #3+1, 1 added by default by getrefcount()