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Home/ Questions/Q 801767
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T23:29:37+00:00 2026-05-14T23:29:37+00:00

A small problem. Any idea guys why this does not work? int? nullableIntVal =

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A small problem. Any idea guys why this does not work?

int? nullableIntVal = (this.Policy == null) ? null : 1;

I am trying to return null if the left hand expression is True, else 1. Seems simple but gives compilation error.

Type of conditional expression cannot be determined because there is no implicit conversion between null and int.

If I replace the null in ? null : 1 with any valid int, then there is no problem.

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  1. Editorial Team
    Editorial Team
    2026-05-14T23:29:37+00:00Added an answer on May 14, 2026 at 11:29 pm

    Yes – the compiler can’t find an appropriate type for the conditional expression. Ignore the fact that you’re assigning it to an int? – the compiler doesn’t use that information. So the expression is:

    (this.Policy == null) ? null : 1;
    

    What’s the type of this expression? The language specification states that it has to be either the type of the second operand or that of the third operand. null has no type, so it would have to be int (the type of the third operand) – but there’s no conversion from null to int, so it fails.

    Cast either of the operands to int? and it will work, or use another way of expessing the null value – so any of these:

    (this.Policy == null) ? (int?) null : 1;
    
    (this.Policy == null) ? null : (int?) 1;
    
    (this.Policy == null) ? default(int?) : 1;
    
    (this.Policy == null) ? new int?() : 1;
    

    I agree it’s a slight pain that you have to do this.


    From the C# 3.0 language specification section 7.13:

    The second and third operands of the
    ?: operator control the type of the
    conditional expression. Let X and Y be
    the types of the second and third
    operands. Then,

    • If X and Y are the same type, then this is the type of the conditional
      expression.

    • Otherwise, if an implicit conversion (§6.1) exists from X to Y, but not
      from Y to X, then Y is the type of the
      conditional expression.

    • Otherwise, if an implicit conversion (§6.1) exists from Y to X, but not
      from X to Y, then X is the type of the
      conditional expression.

    • Otherwise, no expression type can be determined, and a compile-time error
      occurs.

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