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Editorial Team
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Asked: 2026-06-16T01:59:22+00:00

A thread’s run method is invoked by JVM when Thread.start() is called by the

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A thread’s run method is invoked by JVM when Thread.start() is called by the programmer.

  1. What does the JVM do in background before calling Thread.run()?

  2. Why is Thread.run() not exposed to the user?

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1 Answer

  1. Editorial Team

    What does the JVM do in background before calling Thread.run()?

    It does the JVM work to manage the thread object (allocate stack space, thread-locals, …) and the per-architecture native work of forking and scheduling a new thread/process/clone or whatever the architecture uses to implement threads.

    Why is Thread.run() not exposed to the user?

    I assume you are talking about “exposed” in terms of the stack frame. Just like the the static main method, there obviously are call frames above the user code that aren’t exposed to the user because they aren’t useful and would be confusing. I’d say the same thing about the Thread.run() method. It will show up in the call stack if you extend Thread and override run() but won’t if you are passing in a target Runnable.

    I have a lot of details about this in this answer:

    How does Java run() method work?

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