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Home/ Questions/Q 6621271
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T21:14:29+00:00 2026-05-25T21:14:29+00:00

a.zip— — b.txt — c.txt — d.txt Methods to process the zip files with

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a.zip---
      -- b.txt
      -- c.txt
      -- d.txt

Methods to process the zip files with Python,

I could expand the zip file to a temporary directory, then process each txt file one bye one

Here, I am more interested to know whether or not python provides such a way so that
I don’t have to manually expand the zip file and just simply treat the zip file as a specialized folder and process each txt accordingly.

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  1. Editorial Team
    Editorial Team
    2026-05-25T21:14:29+00:00Added an answer on May 25, 2026 at 9:14 pm

    The Python standard library helps you.

    Doug Hellman writes very informative posts about selected modules: https://pymotw.com/3/zipfile/

    To comment on Davids post: From Python 2.7 on the Zipfile object provides a context manager, so the recommended way would be:

    import zipfile
    with zipfile.ZipFile("zipfile.zip", "r") as f:
        for name in f.namelist():
            data = f.read(name)
            print name, len(data), repr(data[:10])
    

    The close method will be called automatically because of the with statement. This is especially important if you write to the file.

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