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Home/ Questions/Q 8741177
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T11:15:54+00:00 2026-06-13T11:15:54+00:00

abstract class foo { public $blah; } class bar extends foo { public $baz;

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abstract class foo
{
    public $blah;
}

class bar extends foo
{
    public $baz;
}

Given that I have a foo class that inherits from the abstract bar class how would I get an array of the instance variables that exist only on bar but not on foo (i.e. properties that are defined on the bar level)? In the example above I would want baz but not blah.

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  1. Editorial Team
    Editorial Team
    2026-06-13T11:15:55+00:00Added an answer on June 13, 2026 at 11:15 am

    As hakre said, use Reflection. Grab the class’s parent class, and do a diff on the properties, like so:

    function get_parent_properties_diff( $obj) {
        $ref = new ReflectionClass( $obj);
        $parent = $ref->getParentClass();
        return array_diff( $ref->getProperties(), $parent->getProperties());
    }
    

    You’d call it like this:

    $diff = get_parent_properties_diff( new bar());
    foreach( $diff as $d) {
        echo $d->{'name'} . ' is in class ' . $d->{'class'} . ' and not the parent class.' . "\n";
    }
    

    See it working in this demo, which outputs:

    baz is in class bar and not the parent class.
    
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