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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T16:18:40+00:00 2026-05-12T16:18:40+00:00

According to http://www.faqs.org/docs/diveintopython/fileinfo_private.html : Like most languages, Python has the concept of private elements:

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According to http://www.faqs.org/docs/diveintopython/fileinfo_private.html:

Like most languages, Python has the
concept of private elements:

  • Private
    functions, which can’t be called from
    outside their module

However, if I define two files:

#a.py
__num=1

and:

#b.py
import a
print a.__num

when i run b.py it prints out 1 without giving any exception. Is diveintopython wrong, or did I misunderstand something? And is there some way to do define a module’s function as private?

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  1. Editorial Team
    Editorial Team
    2026-05-12T16:18:40+00:00Added an answer on May 12, 2026 at 4:18 pm

    In Python, "privacy" depends on "consenting adults’" levels of agreement – you can’t force it. A single leading underscore means you’re not supposed to access it "from the outside" — two leading underscores (w/o trailing underscores) carry the message even more forcefully… but, in the end, it still depends on social convention and consensus: Python’s introspection is forceful enough that you can’t handcuff every other programmer in the world to respect your wishes.

    ((Btw, though it’s a closely held secret, much the same holds for C++: with most compilers, a simple #define private public line before #includeing your .h file is all it takes for wily coders to make hash of your "privacy"…!-))

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