Question

According to me, it is zero but there seems to be bit confusion here

I have tested it with gcc compiler and it gives me zero as output. I know that in C++, size of an empty class is 1. Let me know if I am missing anything here.

Answer 1

A struct cannot be empty in C because the syntax forbids it. Furthermore, there is a semantic constraint that makes behavior undefined if a struct has no named member:

struct-or-union-specifier:
  struct-or-union identifieropt { struct-declaration-list }
  struct-or-union identifier

struct-or-union:
  struct
  union

struct-declaration-list:
  struct-declaration
  struct-declaration-list struct-declaration

struct-declaration:
  specifier-qualifier-list struct-declarator-list ;

/* type-specifier or qualifier required here! */
specifier-qualifier-list:
  type-specifier specifier-qualifier-listopt
  type-qualifier specifier-qualifier-listopt

struct-declarator-list:
  struct-declarator
  struct-declarator-list , struct-declarator

struct-declarator:
  declarator
  declaratoropt : constant-expression

If you write

struct identifier { };

It will give you a diagnostic message, because you violate syntactic rules. If you write

struct identifier { int : 0; };

Then you have a non-empty struct with no named members, thus making behavior undefined, and not requiring a diagnostic:

If the struct-declaration-list contains no named members, the behavior is undefined.

Notice that the following is disallowed because a flexible array member cannot be the first member:

struct identifier { type ident[]; };