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Home/ Questions/Q 6919955
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:05:15+00:00 2026-05-27T10:05:15+00:00

According to MSDN I can create a Uint32Array in 3 ways: new Uint32Array( length

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According to MSDN I can create a Uint32Array in 3 ways:

  1. new Uint32Array( length );
  2. new Uint32Array( array );
  3. new Uint32Array( buffer, byteOffset, length );

First and second method work great, but third didn’t work for me. What’s wrong in this code?

var buffer = new ArrayBuffer(8);
var uint32s = new Uint32Array(buffer, 4, 4);
uint32s[0] = 0x05050505;
var uint8s = new Uint8Array(buffer);
for (var i =0; i< 8; i++)
{
    alert(uint8s[i]);
}

This works fine, but of course byteOffset = 0.

var uint32s = new Uint32Array(buffer);
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  1. Editorial Team
    Editorial Team
    2026-05-27T10:05:15+00:00Added an answer on May 27, 2026 at 10:05 am

    It seems that the documentation is incorrect here in that length is not a number of bytes but the number of 32-bit integers that the Uint32Array will contain.

    Exhibit A

    Changing the code to var uint32s = new Uint32Array(buffer, 4, 1); works.

    Exhibit B

    The documentation for Uint32Array on MDN says that length is a count of items, not bytes.

    Exhibit C

    It doesn’t really make sense to have the constructor accept a length in bytes. What should happen if length is not a multiple of 4?

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