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Home/ Questions/Q 6241979
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T11:52:02+00:00 2026-05-24T11:52:02+00:00

According to msdn the general standart for datetime is select convert(datetime,’19781222′,112) //YYYYMMDD So if

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According to msdn the general standart for datetime is

select convert(datetime,'19781222',112)       //YYYYMMDD

So if i want to insert into datetime this value i can do it by

update [Readings] set  [StartDate] = '19781222'

But what about time ? how do i add the Time to the YYYYMMDD ?

Question 2 : how do i update only the time in DateTime ?

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  1. Editorial Team
    Editorial Team
    2026-05-24T11:52:02+00:00Added an answer on May 24, 2026 at 11:52 am

    1st part:

     update [Readings] 
     set  [StartDate] = '19781222 10:23:56'   -- YYYYMMDD 
    

    2nd:

    update [Readings] 
    set  [StartDate] = DATEADD(dd, DATEDIFF(dd, 0, [StartDate]), 0) + '12:34:37'
    

    The ultimate guide to the datetime datatypes

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