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According to my class notes, you can allocate an array in C++ like
int *A = new int[5]
where A is a pointer to the array.
But then you can access the array as A[3]. Why can you do that? Isn’t A a pointer and not the actual array?
The indexing
operator[]actually defined to work on pointers, not on arrays.A[3]is actually a synonym for*(A+3). It works on arrays as a consequence of the fact that arrays can be implicitly converted to pointers to their first element.