According to the feedparser documentation, I can turn an RSS feed into a parsed object like this:
import feedparser d = feedparser.parse('http://feedparser.org/docs/examples/atom10.xml')
but I can’t find anything showing how to go the other way; I’d like to be able do manipulate ‘d’ and then output the result as XML:
print d.toXML()
but there doesn’t seem to be anything in feedparser for going in that direction. Am I going to have to loop through d’s various elements, or is there a quicker way?
Appended is a not hugely-elegant, but working solution – it uses feedparser to parse the feed, you can then modify the entries, and it passes the data to PyRSS2Gen. It preserves most of the feed info (the important bits anyway, there are somethings that will need extra conversion, the parsed_feed[‘feed’][‘image’] element for example).
I put this together as part of a little feed-processing framework I’m fiddling about with.. It may be of some use (it’s pretty short – should be less than 100 lines of code in total when done..)