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Home/ Questions/Q 6891865
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T06:27:48+00:00 2026-05-27T06:27:48+00:00

According to the following program, I can understand that, const keyword at a front

  • 0

According to the following program, I can understand that, const keyword at a front of a references means Const Reference to const value, correct?

#include <iostream>
using namespace std;

struct s
{
    int x;
};

int main(void)
{
    s a = {10}, b = {30};

    // IN POINTERS ----------------
    const s* ptrToConstValue;
    ptrToConstValue= &a;
    //ptrToConstValue->x = 30; 
    ptrToConstValue = &b;

    s* const constPtrToNonConstVaue = &a;
    constPtrToNonConstVaue->x = 40;
    //constPtrToNonConstVaue = &b;

    const s* const constPtrToConstValue = &a;
    //constPtrToConstValue = &b;
    //constPtrToConstValue->x = 30;


    // IN REFERENCES -------------
    const s& seemsToBeConstRefToConstValue = a;
    //s = b;
    //s.x = 30;

    return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-05-27T06:27:49+00:00Added an answer on May 27, 2026 at 6:27 am

    References are always const, so you don’t need the const keyword for
    them; it is, in fact, forbidden.

    So you have:

    S*                ps;   //  Non-const pointer to a non-const value
    S const*          psc;  //  Non-const pointer to a const value
    S* const          pcs;  //  Const pointer to a non-const value
    S const* const    pcsc; //  Const pointer to a const value
    

    , but only:

    S&                rs;   //  (const) reference to a non-const value
    S const&          rsc;  //  (const) reference to a const value
    

    The const which immediately follows the name of the type can be moved
    to the beginning of the declaration, at the cost of some confusion to
    the reader.

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