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Home/ Questions/Q 3872674
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T21:57:05+00:00 2026-05-19T21:57:05+00:00

According to the Java Language Specification , constructors cannot be marked synchronized because other

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According to the Java Language Specification, constructors cannot be marked synchronized because other threads cannot see the object being created until the thread creating it has finished it. This seems a bit odd, because I can indeed have another thread view the object while it’s being constructed:

public class Test {
    public Test() {
       final Test me = this;
       new Thread() {
           @Override
           public void run() {
               // ... Reference 'me,' the object being constructed
           }
       }.start();
    }
}

I know that this is a pretty contrived example, but it seems in theory that someone could come up with a more realistic case where marking the constructor synchronized would be legitimate in order to prevent races with threads like this one.

My question is this: is there a reason that Java would specifically disallow the synchronized modifier on a constructor? Perhaps my above example is flawed, or perhaps there really is no reason and it’s an arbitrary design decision. In either case, I’m really curious and would love to know the answer.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T21:57:06+00:00Added an answer on May 19, 2026 at 9:57 pm

    If you really need synchronization of the rest of the constructor versus any threads which anyhow gets a reference to your not-yet-totally-constructed object, you can use a synchronized-block:

    public class Test {
        public Test() {
           final Test me = this;
           synchronized(this) {
              new Thread() {
                 @Override
                 public void run() {
                    // ... Reference 'me,' the object being constructed
                    synchronized(me) {
                       // do something dangerous with 'me'.
                    }
                 }
              }.start();
              // do something dangerous with this
           }
        }
    }
    

    Usually it is considered bad style to “give out” your not-yet-constructed object like this, so a synchronized constructor is not necessary.


    In some corner cases a synchronized constructor would be useful. Here is a more realistic example, from the discussion of Bozho’s answer:

    public abstract class SuperClass {
    
       public SuperClass() {
           new Thread("evil") { public void run() {
              doSomethingDangerous();
           }}).start();
           try {
              Thread.sleep(5000);
           }
           catch(InterruptedException ex) { /* ignore */ }
       }
    
       public abstract void doSomethingDangerous();
    
    }
    
    public class SubClass extends SuperClass {
        int number;
        public SubClass () {
            super();
            number = 2;
        }
    
        public synchronized void doSomethingDangerous() {
            if(number == 2) {
                System.out.println("everything OK");
            }
            else {
                System.out.println("we have a problem.");
            }
        }
    
    }
    

    We want that the doSomethingDangerous() method is only called after construction of our SubClass object is complete, e.g. we only want the “everything OK” output. But in this case, when you only can edit your SubClass, you have no chance of achieving this. If the constructor could be synchronized, it would solve the problem.

    So, what we learn about this: never do something like I did here in the superclass constructor, if your class is not final – and don’t call any non-final methods of your own class from your constructor.

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