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Home/ Questions/Q 7826727
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T09:32:54+00:00 2026-06-02T09:32:54+00:00

according to the manual you can use such syntax: libfoo(obj1.o) , which stands for

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according to the manual you can use such syntax: libfoo(obj1.o) , which stands for insert obj1.o to libfoo, i wrote a rule like this:

libfoo(obj1.o obj2.o):obj1 obj2  

this rule only insert obj1.o to libfoo, why it just can not insert obj2.o into libfoo?
what does libfoo(obj1.o obj2.o) really stands for?

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  1. Editorial Team
    Editorial Team
    2026-06-02T09:32:59+00:00Added an answer on June 2, 2026 at 9:32 am

    From the GNUMake manual:

    To specify several members in the same archive, you can write all the
    member names together between the parentheses. For example:

     foolib(hack.o kludge.o)
    

    is equivalent to:

     foolib(hack.o) foolib(kludge.o)
    

    When you make, I’m guessing you don’t specify the target, so Make chooses the first target, which in your makefile is libfoo(obj1.o).

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