Question

According to this site, I have done the following program which sorts strings.

#include <cstdlib>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char list[5][4]={"dat","mai","lik","mar","ana"};
int main(int argc, char *argv[])
{
    int x;
    puts("sortirebamde:");
     for (x=0;x>sizeof(list)/sizeof(char);x++)
     printf("%s\n",list[x]);
      qsort(&list,(sizeof(list)/sizeof(char)),sizeof(list[0]),strcmp);
    system("PAUSE");
    return EXIT_SUCCESS;
}

Here is the error I get

13 C:\Documents and Settings\LIBRARY\Desktop\string_sortireba.cpp invalid conversion from `int (*)(const char*, const char*)' to `int (*)(const void*, const void*)' 
13 C:\Documents and Settings\LIBRARY\Desktop\string_sortireba.cpp   initializing argument 4 of `void qsort(void*, size_t, size_t, int (*)(const void*, const void*))' 

Please help

Answer 1

Please note: It is unusual to store C strings in two dimensional char arrays. It’s more normal to have char *ary[], such as argv. That type cannot be sorted directly using qsort and strcmp, because qsort will pass char ** not char * to the comparison function. This is good for efficiency, the pointers can be swapped instead of the whole strings. The Linux manpage for qsort has some good example code with a correct comparison function.

You can’t pass strcmp directly to qsort as its comparison function because qsort expects to pass pointers to void where strcmp expects pointers to const char. Given the required similarity between pointers to void and pointers to char, you could probably do it with a cast (for your code), but the cleaner way would be to write a function that takes the right types:

int cmpstr(void const *a, void const *b) { 
    char const *aa = (char const *)a;
    char const *bb = (char const *)b;

    return strcmp(aa, bb);
}

Note, however, that in C++ you’d normally want to use std::sort instead of qsort, and probably use std::string instead of char *, which case the sorting gets a lot simpler (and generally faster as well).