Question

Actually I am very new to PHP.
My code goes here:

<?php
$mysql = mysql_connect('localhost','Susi','susi');
mysql_select_db('mydb', $mysql);
$rs = mysql_query("show tables;");
$nonTable = array('table_1','table_2');

while ($tabs = mysql_fetch_assoc($rs)) {
   foreach ($tabs as $tables) {
   echo  $tables.'<br />';
  }
 }
?>

In this case $rs stores the entire table of the database “mydb” .
There is another array $nontable which contains some tables which are already in Table list of “mydb” database.

I want to pass those table names to the while loop excluding the tables in “$nontable” array.

I tried

 array_diff($rs,$nontable)

but it provided NULL result.

I will be very happy if somebody helps me out…

Thanks in advance…

Answer 1

Do you mean:

while ($tabs = mysql_fetch_assoc($rs)) {
   foreach ($tabs as $tables) {
      if(!in_array($tables, $nonTable)) {
        echo $tables."<br />";
      }
  }
}