Question

actually I save date in database in varchar format.
firstly I retrieve date from databae & store it into $date.
now i want to perform addition of 5 days with $date1.

when i search on internet i got this code :

$date = date('Y-m-d', strtotime("+5 days"));

now can you tell me how I insert $date1 value to this code for get expected result.

Answer 1

Working with strtotime you could to something like this:

<?php

$date = "2010-04-01";

echo date("Y-m-d", strtotime("+5 days", strtotime($date))); // 2010-04-06

The first strtotime($date) call converts the string into an timestamp integer, the secound call takes that integer and adds 5 days to it. Then date formats it back into a string

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On a sidenote:

There is not really a need to save a date as a varchar since mysql (which i guess is what you are using from the tag) will also work with “DATETIME” fields for you. E.g. SELECT DATETIMEFIELD FROM table will return ‘2010-01-01 00:00:00’ or a “DATE” field will return “2010-01-01”, both are strtotime parseable 🙂