Question

# admin.py
class CustomerAdmin(admin.ModelAdmin):  
    list_display = ('foo', 'number_of_orders')


# models.py
class Order(models.Model):
    bar = models.CharField[...]
    customer = models.ForeignKey(Customer)

class Customer(models.Model):
    foo = models.CharField[...]

    def number_of_orders(self):
        return u'%s' % Order.objects.filter(customer=self).count()  

How could I sort Customers, depending on number_of_orders they have?

admin_order_field property can’t be used here, as it requires a database field to sort on. Is it possible at all, as Django relies on the underlying DB to perform sorting? Creating an aggregate field to contain the number of orders seems like an overkill here.

The fun thing: if you change url by hand in the browser to sort on this column – it works as expected!

Answer 1

I loved Greg’s solution to this problem, but I’d like to point that you can do the same thing directly in the admin:

from django.db import models

class CustomerAdmin(admin.ModelAdmin):
    list_display = ('number_of_orders',)

    def get_queryset(self, request):
    # def queryset(self, request): # For Django <1.6
        qs = super(CustomerAdmin, self).get_queryset(request)
        # qs = super(CustomerAdmin, self).queryset(request) # For Django <1.6
        qs = qs.annotate(models.Count('order'))
        return qs

    def number_of_orders(self, obj):
        return obj.order__count
    number_of_orders.admin_order_field = 'order__count'

This way you only annotate inside the admin interface. Not with every query that you do.