Question

After a while, I was finally able to pass a pointer to a function like this:

function originalFunction($value) {
  print "I am in the function, with value $value";
}

function testFunctionPointer($functionName, $id) {
  $functionName($id);
}

$test = testFunctionPointer("originalFunction", 200);

Basically, I realized that if you pass a STRING and you use that string as a function name, the function is executed.
In fact, in the example above, the “originalFunction” is correctly called.

But how can I get the parameter working? It’s always zero…

PS: I know that what I am doing is not clean, it shouldn’t be done, etc. etc. etc. But it’s just for an INTERNAL PROJECT I am doing for MYSELF, so nobody will get hurt by this 😉

Thank you in advance!

Answer 1

Your code is executing well for me, outputting 200 as expected.

Also you can directly call it like this:

call_user_func("originalFunction", 200);