Question

After applying some commands I have a data set as below

graph_name=abc
group_name=def
factory=xyz
export a=1
export b=2
export c=3

Now how can i acheieve the below output

graph_name=abc
export a=1
export b=2
export c=3

I need all the export statements in addition with just graph_name containing record.

Answer 1

sed -n -e '/^graph_name=/p' -e '/^export /p' your-file

This doesn’t print by default (-n); it then explicitly prints those lines that match what you want.