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Home/ Questions/Q 6232047
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T10:02:51+00:00 2026-05-24T10:02:51+00:00

After checking for both fread and fopen with the search-command php fread php code

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After checking for both fread and fopen with the search-command “php fread php code” and php fopen php code” without success I’m now turning to asking the question myself. (Over 300 pages with questions were a bit to steep to dig around in.)

I have a page where I get the content from external files. I got the index.php with the links which sends requests through the url (?links=home, for example) that is read from another file that looks through an array and finds the right file. All that works! But here is the tricky part:
On of the files includes a few strings of php-codes that won’t do it’s job but just hangs around in the view-source. Yes, you can see the commands in the source:code, but it won’t anything I request. Not a single echo.

Here is some code that might explain things even better.

The code that gets the url-command:

<?php
function load_pages() {
    if ($_GET['link'] != NULL) {
        $link = $_GET['link'];
        $links = array("hem" => "hem.php", "about" => "about.php", "blogg" => "blogg.php", "kontakta" => "kontakta.php");
        foreach ($links as $key => $value) {
            if ($key == $link) {
                $file = "links/" . $value;
                $fh = fopen($file, "r") or exit("Unable to open the file.");
                $fileContent = fread($fh, filesize($file));
                fclose($fh);
                echo $fileContent;
            }
        }
    } else {
        $file = "links/hem.php";
        $fh = fopen($file, "r") or exit("Unable to open the file.");
        $fileContent = fread($fh, filesize($file));
        fclose($fh);
        echo $fileContent;
    }
}
?>

The file that gets the command for the page I want to load:

<?php
include ("../include/functions.php");
connect();
?>

<h1>Blogg</h1>
<?php
if ($_GET['id'] == NULL) {
    blogg_content();
} else {
    blogg_link();
}
?>

<div id="blogg_menu">
    <?php blogg_menu(); ?>
</div>

What comes out is: Blogg
That just doesn’t do the trick, so what might I change to make it give me the blog-content and such? (The page is on Swedish, just to disclaim any typos about “Blogg”.)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T10:02:53+00:00Added an answer on May 24, 2026 at 10:02 am

    If those files contain PHP code that you want to be executed you need to include or require them rather than echoing the raw data.

    Please see PHP’s documentation on how to include code files.

    EDIT
    Kind of hard to tell from your description but if at all, you would have to do something like:

    ...
    if ($key == $link) {
        $file = "links/" . $value;
        include_once $file;
    }
    ...
    
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