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Home/ Questions/Q 802385
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T23:35:36+00:00 2026-05-14T23:35:36+00:00

After executing a XPath expression for extracting all year and value elements associated with

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After executing a XPath expression for extracting all year and value elements associated with death rates from a XML DB file, I want to take each node from the node list and find the year node, print that, find the value node, and print that all separately. The problem is that the output does not show anything.

The XML content looks like this:

<dataset type="country" name="Afghanistan" total="222">
...
        <data>
             <country id="AFG">Afghanistan</country>
             <indicator id="SP.DYN.CDRT.IN">Death rate, crude (per 1,000 people)</indicator>
             <year>2006</year>
             <value>20.3410000</value>
           </data>
           <data>
             <country id="AFG">Afghanistan</country>
             <indicator id="SP.DYN.CDRT.IN">Death rate, crude (per 1,000 people)</indicator>
             <year>2007</year>
             <value>19.9480000</value>
           </data>
           <data>
             <country id="AFG">Afghanistan</country>
             <indicator id="SP.DYN.CDRT.IN">Death rate, crude (per 1,000 people)</indicator>
             <year>2008</year>
             <value>19.5720000</value>
           </data>
           <data>
             <country id="AFG">Afghanistan</country>
             <indicator id="IC.EXP.DOCS">Documents to export (number)</indicator>
             <year>2005</year>
             <value>7.0000000</value>
           </data>
           <data>
             <country id="AFG">Afghanistan</country>
             <indicator id="IC.EXP.DOCS">Documents to export (number)</indicator>
             <year>2006</year>
             <value>12.0000000</value>
           </data>
           <data>
             <country id="AFG">Afghanistan</country>
             <indicator id="IC.EXP.DOCS">Documents to export (number)</indicator>
             <year>2007</year>
             <value>12.0000000</value>
           </data>
...
</dataset>

The Perl code looks like this:

#Use XML Xlib parser to find elements related to death rate

my $parser = XML::LibXML->new();
my $tree = $parser->parse_file($XML_DB);
my $root = XML::LibXML::XPathContext->new($tree->documentElement());
#print $nodeSet->to_literal(); 

foreach my $node ($root->findnodes("/*/data/indicator[\@id = 'SP.DYN.CDRT.IN']/following-sibling::*")) {
    #print $node->textContent() . "\n";
    #print $node->nodeName . "\n";
    print $node->find("year") . "\n";
}
exit;
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T23:35:37+00:00Added an answer on May 14, 2026 at 11:35 pm

    The expression year in find("year") does not do work like you think it does because your complicated selector does not end up at the data node. Use Xacobeo to debug XPath expressions. This works:

    foreach my $node ($root->findnodes(q{/*/data/indicator[@id = 'SP.DYN.CDRT.IN']/following-sibling::*})) {
        say $_->toString for $node->childNodes;
    }
    

    Output:

    2006
    20.3410000
    2007
    19.9480000
    2008
    19.5720000
    
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