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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T03:10:44+00:00 2026-06-01T03:10:44+00:00

After it turned out that what I originally wanted is probably not possible w/o

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After it turned out that what I originally wanted is probably not possible w/o involving C++11 I want to slightly change the requirement and ask you if this can be achieved.

previous question

Basically I want to check in compile time if a class is inheriting from “interface”. By interface I mean class with pure virtual methods only.
I would like to do the following code:

template <typename T>
class Impl : public T {
public:
STATIC_ASSERT_INTERFACE(T);
};

The behavior here is if T has only pure virtual methods then it will compile and if one of its methods is not then fail.

Can anyone think of something like that?

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  1. Editorial Team
    Editorial Team
    2026-06-01T03:10:45+00:00Added an answer on June 1, 2026 at 3:10 am

    This is basically similar to Java interfaces. In C++, there is no existence of interface as such, it’s just a terminology used for a class with all pure-virtual methods and only static const data members.

    Additionally, pure virtual methods may or may not have a function body. Thus C++ pure virtual methods are not exactly same as Java’s abstract methods.

    Unfortunately what you are asking is not possible to simulate in C++.

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