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Home/ Questions/Q 805667
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T00:07:04+00:00 2026-05-15T00:07:04+00:00

After load content to page using div.load(‘page.php’); I need get all of links from

  • 0

After load content to page using

div.load('page.php');

I need get all of links from page to change them. So I wrote this:

div.load('page.php', function() {
    links = $('a');
    alert(links.length);

    for(i=0 ; i<links.length ; i++
    {
        link = $('a:nth-child('+(i+1)+')');
        alert(link.attr('href'));
    }
});

The result of this code is:
– first alert() returned correct links quantity, but it’s not a DOM objects, so I can’t change href attribute using it: links[i].attr(‘href’, ‘changed’)
and I have to getting links in loop one by one, but this method returned only first link from page.php and all of links from site which will not changed.

Have someone any idea how do it?

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  1. Editorial Team
    Editorial Team
    2026-05-15T00:07:04+00:00Added an answer on May 15, 2026 at 12:07 am

    You can do like:

    div.load('page.php', function() {
        $('a').each(function(index){
          alert($(this).attr('href'));
        });
    });
    

    You can change their href like:

    div.load('page.php', function() {
        $('a').each(function(index){
          $(this).attr('href', 'whatever');
        });
    });
    
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