Question

after reading inputs to an array:

int * inputs;

the “inputs” is 1 dimensional array: inputs[6], then reading this array out, the values are:

inputs[0]=1
inputs[1]=2
inputs[2]=3
inputs[3]=4
inputs[4]=5
inputs[5]=6

I would like to read this array into another one dimensional array:

int counter=0;
int * allElements = new int[6];

for(int i=0; i<6; i++)
{
      allElements[counter++] = inputs[i];
}

That is a traditional way of reading all of the elements into one dimensional array and I believe if I read the elements of “allElements” this way:

for(int i=0; i<6; i++)
   printf("%d ", allElements[i]);

and it should be: 1 2 3 4 5 6

However, I would like to read all elements of that array into the 1 dimensional array such that when I do it like this:

for(int i=0; i<6; i++)
   printf("%d ", allElements[i]);

It should be: 1 3 5 2 4 6

How can I achieve this way?

Answer 1

What about:

for(int i=0; i<6; i++)
{
    allElements[i] = inputs[2*(i%3) + (i/3)];
}

Imagine inputs is a two-dimension array, of 3×2, then i%3 is one coordinate and i/3 the other. Just transpose it into a 2×3 matrix, and done!