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Asked: May 11, 20262026-05-11T12:08:50+00:00 2026-05-11T12:08:50+00:00

After using the ‘solve’ function on an equation with one variable, it seems like

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After using the ‘solve’ function on an equation with one variable, it seems like Matlab doesn’t like using floating point. So, my answer is

ans = -2515439103678008769411809280/29019457930552314063110978530889-1/232155663444418512504887828247112*13479465975722384794797850090594238631144539220477565900842902305^(1/2) 

and I’m not sure what the best way to convert it to an understandable decimal is. The best way I have so far is

eval(char(ans)) 

(which gives me -0.5002 for those keeping track), but I’m not really happy with that solution.

Can anyone suggest something better?

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  1. 2026-05-11T12:08:50+00:00Added an answer on May 11, 2026 at 12:08 pm

    Well, the very next page I looked at had the answer. It’s the ‘double’ function:

    double(ans) 
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