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Home/ Questions/Q 1018459
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T10:51:37+00:00 2026-05-16T10:51:37+00:00

AFunc changes what was sent to it, and the printf() outputs the changes: void

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AFunc changes what was sent to it, and the printf() outputs the changes:

void AFunc ( char *myStr, int *myNum )
{
    *myStr = 's';
    *myNum = 9;
}


int main ( int argc, char *argv[] )
{
   char someString = 'm';
   int n = 6;

   AFunc(&someString, &n);

   printf("%c" "%d", someString, n);
}

But what if the string was more than one char? How would the code look differently? Thanks for any help.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T10:51:38+00:00Added an answer on May 16, 2026 at 10:51 am

    If it were a “string” instead of a char, you would do something like this:

    #include <stdio.h>
    
    void AFunc (char *myStr, int *myNum) {
        myStr[0] = 'p'; // or replace the lot with strcpy(myStr, "pax");
        myStr[1] = 'a';
        myStr[2] = 'x';
        myStr[3] = '\0';
        *myNum = 9;
    }
    
    int main (void) {
        char someString[4];
        int n = 6;
    
        AFunc(someString, &n);
    
        printf("%s %d", someString, n);
        return 0;
    }
    

    which outputs:

    pax 9
    

    A “string” in C is really an array of characters terminated by the \0 (NUL) character.

    What the above code does is to pass in the address of the first character in that array and the function populates the four characters starting from there.

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