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Editorial Team
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Asked: 2026-06-10T19:51:32+00:00

Agility newbie here. Given input text: <html> … Lots of html here… <label class=list_item_title>Yes</label><br

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Agility newbie here. Given input text:

<html>
  ... Lots of html here...
  <label class="list_item_title">Yes</label><br /><br />
    <div class="list_item">
        <div style="width:425px;" class="left"><a href="/xyz">HIT1</a>  (2012)</div>
        <div style="width:190px;" class="right"></div>
    </div>
    <div class="list_item">
        <div style="width:425px;" class="left"><a href="/abc">HIT2</a>  (2012)</div>
        <div style="width:190px;" class="right"></div>
    </div>
  <label class="list_item_title">No</label><br /><br />
  <div class="list_item">
        <div style="width:425px;" class="left"><a href="/xyz">IGNORE</a>  (2012)</div>
        <div style="width:190px;" class="right"></div>
  </div>
  ... Lots of html here...
</html>

I want to get HIT1 & HIT2.

Basically the algorithm is to find the innerText of all A after the label node (class=”list_item_title”) where innerText=”Yes”

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1 Answer

  1. Editorial Team

    This XPath expression works for your example:

    //a[preceding::label[1][text()="Yes"]]/text()

    It looks for all a whose first preceding label contains Yes and returns their text().

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