Question

Aim to Achieve:

I want all objects where name attribute contains any word from the list.

I have:

list = ['word1','word2','word3']
ob_list = data.objects.filter( // What to write here ?  )
// or any other way to get the objects where any word in list is contained, in 
// the na-me attribute of data.

For example:

if name="this is word2": Then object with such a name should be returned since word2 is in the list.

Please help!

Answer 1

You could use Q objects to constuct a query like this:

from django.db.models import Q

ob_list = data.objects.filter(reduce(lambda x, y: x | y, [Q(name__contains=word) for word in list]))

Edit:

reduce(lambda x, y: x | y, [Q(name__contains=word) for word in list]))

is a fancy way to write

Q(name__contains=list[0]) | Q(name__contains=list[1]) | ... | Q(name__contains=list[-1])

You could also use an explicit for loop to construct the Q object.