Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8114097
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 6, 20262026-06-06T03:02:56+00:00 2026-06-06T03:02:56+00:00

all! I have the following problem: I have 2 simple tables. The first one,

  • 0

all! I have the following problem: I have 2 simple tables. The first one, say, “currency”, stores the information about the currencies (ISO 4217 code (PK), name, etc.). The second one, “rates”, has the following fields: id, currency_code (references currency.code), date_added (datetime), rate.

What I want to fo is to select the latest exchange rates for several currency codes. First, I wanted to do it like this:

SELECT r.rate
FROM rates r
WHERE r.id IN (SELECT id
               FROM rates r1
               WHERE r1.currency_code IN('USD', 'EUR')
               GROUP BY r1.currency_code
               ORDER BY r1.date_added DESC)
ORDER BY r.currency_code ASC

but I soon remembered that the ORDER clause will be taken into account after the results are grouped. In my case, the subquery ended up returning the ids of the earliest rates…

I suppose I could get the rates for each currency code separately, but I still hope that I’ll be able to use a single clean query.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-06T03:02:57+00:00Added an answer on June 6, 2026 at 3:02 am

    Assuming that the latest exchange rate is the one with the highest id you can use:

    SELECT *
    FROM rates r
    WHERE r.id IN (
        SELECT MAX(r1.id)
        FROM rates r1
        GROUP BY r1.currency_code
    ) T;
    

    But I strongly suggest another pattern I love. I explained it in another answer this morning:

    SELECT
      c.*,
      r1.*
    FROM currency c
    INNER JOIN rates r1 ON c.code = r1.currency_code
    LEFT JOIN rates r2 ON r1.currency_code = r2.currency_code AND r2.id > r1.id
    WHERE r2.id IS NULL;
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Good day to all, I have the following problem I have to convert the
I've got the following tables: magazine_tags news_tags page_tags content_tags faq_tags They all have exactly
I have the following query (all tables are innoDB) INSERT INTO busy_machines(machine) SELECT machine
I have the following case: All boats have a boat type like shark ,
I have following statement for query articles from some sections Article.all(:joins => :sections, :conditions
I have following setup, but when I put 1024 and replace all 512 with
I have the following program to browse all virtual directories and their sub directories
I have a following Kohana setup: All my files are placed under 'public_html/koh' My
A noob question. I'm putting together my first database and have the following design
I have the following problem (simplified): I have a table that contains animals, e.g:

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.