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Home/ Questions/Q 6696729
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T06:22:33+00:00 2026-05-26T06:22:33+00:00

all, If you use boost pool library, how would you replace the following statement:

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all,

If you use boost pool library, how would you replace the following statement:

MyStruct *someStruct = (MyStruct *) calloc(numOfElements, sizeof(MyStruct));

If it was for one element, I would do:

boost::object_pool<MyStruct> myPool;
MyStruct *someStruct = myPool.malloc();

but since “numOfElements” is a variable, I have the feeling executing a loop of malloc() is not a good idea?

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  1. Editorial Team
    Editorial Team
    2026-05-26T06:22:33+00:00Added an answer on May 26, 2026 at 6:22 am

    I’d say you need to use pool_alloc interface:

    static pointer allocate(size_type n);
    static pointer allocate(size_type n, pointer);
    static void deallocate(pointer ptr, size_type n);
    

    Sample from http://www.boost.org/doc/libs/1_47_0/libs/pool/doc/interfaces.html

    void func()
    {
        std::vector<int, boost::pool_allocator<int> > v;
        for (int i = 0; i < 10000; ++i)
            v.push_back(13);
    } // Exiting the function does NOT free the system memory allocated by the pool allocator
      // You must call
      //  boost::singleton_pool<boost::pool_allocator_tag, sizeof(int)>::release_memory()
      // in order to force that
    
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