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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T21:02:40+00:00 2026-06-01T21:02:40+00:00

All the info I can find in documentation and the web for -ffinite-math-only is

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All the info I can find in documentation and the web for -ffinite-math-only is “Allow optimizations for floating-point arithmetic that assume that arguments and results are not NaNs or +-Infs.” This does not seem forthcoming to me. Does anyone know exactly what those optimizations are?
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  1. Editorial Team
    Editorial Team
    2026-06-01T21:02:42+00:00Added an answer on June 1, 2026 at 9:02 pm

    Lots of little things can be optimized under that assumption, like:

    • x == x –> 1
    • x * 1 –> x
    • x >= y –> !(x < y) and similar.
    • x/x –> 1 if the compiler can prove x != 0.
    • it may allow a compiler to use hardware max/min instructions for expressions like x > y ? x : y.
    • … lots more

    You often see this assumption together with assumptions like “sign of zero doesn’t matter”, which then allows things like:

    • x - x –> 0
    • 0 / x –> 0
    • x * 0 –> 0
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