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Home/ Questions/Q 3393496
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T04:03:27+00:00 2026-05-18T04:03:27+00:00

Alright I have the MYSQL query code setup to pull this information out of

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Alright I have the MYSQL query code setup to pull this information out of my database. What I would like to do now is count by code but group it by name.

$sql = "SELECT  m.* 
          FROM (SELECT DISTINCT Code  
                  FROM Transaction) md 
          JOIN Transaction m ON m.ID_Transaction = (SELECT  ID_Transaction
                                                      FROM Transaction mi
                                                     WHERE mi.Code = md.Code 
                                                       AND Date_Time=CURdate() 
                                                       AND Time_Stamp!=''
                                                  ORDER BY m.Name DESC, mi.Code DESC, mi.Date_Time DESC, mi.ID_Transaction DESC
                                                     LIMIT 1)";

With my php code this is what i get from this query.

rick, 002455, 2010-11-10, 08:30 AM  
rick, 003819, 2010-11-10, 08:45 AM  
amber, 003572, 2010-11-10, 08:45 AM  
eric, 001479, 2010-11-10, 10:30 AM  
jerry, 001012, 2010-11-10, 09:45 AM   

rick being name
000000 being code

I want to take this information and count it like so for each name.

rick = 2  
amber = 1  
eric = 1  
jerry = 1  

I’m not sure how I would do this? Can I use the information in the query to make another query to count this information.

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  1. Editorial Team
    Editorial Team
    2026-05-18T04:03:28+00:00Added an answer on May 18, 2026 at 4:03 am
    SELECT m.name, count(*) FROM (
    SELECT DISTINCT Code
    FROM Transaction
    ) md JOIN Transaction m ON
    m.ID_Transaction = ( SELECT ID_Transaction FROM Transaction mi WHERE mi.Code = md.Code AND Date_Time=CURdate() AND Time_Stamp!='' ORDER BY m.Name DESC, mi.Code DESC, mi.Date_Time DESC, mi.ID_Transaction DESC LIMIT 1 )
     group by m.name
    
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