Question

Alright, PHP is throwing this error at me (in the log) when I run the code mentioned below:

Error

mysql_num_rows() expects parameter 1 to be resource, string given in (place) on line 10

Line 9-11

$queryFP = ("SELECT * FROM db");
$countFP = mysql_num_rows($queryFP);
$aID = rand(1, $countFP);

I think it has something to do with the $queryFP’s syntax, but I’m not completely sure how to fix it since $queryFP’s syntax is the simplest query I’ve ever seen.

Answer 1

You need to query the database first.

$queryFP = ("SELECT * FROM db");

Should be:

$queryFP = mysql_query("SELECT * FROM db");