Question

Alright so I have a table, in this table are two columns with ID’s. I want to make one of the columns distinct, and once it is distinct to select all of those from the second column of a certain ID.

Originally I tried:

select distinct inp_kll_id from kb3_inv_plt where inp_plt_id = 581;

However this does the where clause first, and then returns distinct values.

Alternatively:

select * from (select distinct(inp_kll_id) from kb3_inv_plt) as inp_kll_id where inp_plt_id = 581;

However this cannot find the column inp_plt_id because distinct only returns the column, not the whole table.

Any suggestions?

Edit:

Each kll_id may have one or more plt_id. I would like unique kll_id’s for a certain kb3_inv_plt id.

| inp_kll_id | inp_plt_id |
|       1941 |      41383 |
|       1942 |      41276 |
|       1942 |      38005 |
|       1942 |      39052 |
|       1942 |      40611 |
|       1943 |       5868 |
|       1943 |       4914 |
|       1943 |      39511 |
|       1944 |      39511 |
|       1944 |      41276 |
|       1944 |      40593 |
|       1944 |      26555 |

Answer 1

If you do mean, by “make distinct”, “pick only inp_kll_ids that happen just once” (not the SQL semantics for Distinct), this should work:

select inp_kll_id
 from kb3_inv_plt
 group by inp_kll_id
 having count(*)=1 and inp_plt_id = 581;