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Home/ Questions/Q 6975715
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T17:24:14+00:00 2026-05-27T17:24:14+00:00

Alright so I have the query (SELECT * FROM jokes WHERE flags < 5

  • 0

Alright so I have the query

(SELECT * FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC)
UNION
(SELECT * FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC)
UNION
(SELECT * FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC)
 LIMIT 0, 30

and I will run the same thing using COUNT(*) with no limit

(SELECT COUNT(*) FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC)
UNION
(SELECT COUNT(*) FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC)
UNION
(SELECT COUNT(*) FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC)

Essentially what I would like to do is get the count of total results(without the limit), and also get the limited list.

The problem I am having is that when I run the count query, I’m getting a bigger number than the results I get back. The reason for this I’m guessing is when I get the results back, it filters out all the overlapping rows, where as the count only counts each, as I manually have to add them.

Any ideas on how to clean up this whole process?

Also, please note that the number of select statements changes dynamically, but I was hoping there was a way to get a general count that accounts for duplicates.

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T17:24:15+00:00Added an answer on May 27, 2026 at 5:24 pm

    How about this for the Count:

    SELECT COUNT(DISTINCT Id)
    FROM (SELECT Id From jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) 
          UNION
          SELECT Id From jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) 
          UNION
          SELECT Id From jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?)) t
    

    This should give you the unique count, and also notice that I got rid of the order by because it’s not worth calculating for a count query.

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