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Home/ Questions/Q 7179459
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T17:08:40+00:00 2026-05-28T17:08:40+00:00

Alright, so I’m having a bit of an issue here. Here is the loop.

  • 0

Alright, so I’m having a bit of an issue here.
Here is the loop.

lock (ClientLocker)
{
    Trace.WriteLine("#WriteAll: " + sm.Header);
    foreach (Client c in Clients)
    {
        if (c.LoggedIn)
        {
            Trace.WriteLine("#TryWriteTo[" + c.Id + "](" + sm.Header + ")");
            LazyAsync.Invoke(() => c.WriteMessage(sm));
        }
    }
}

Here is LazyAsync

public static class LazyAsync
{
    public static void Invoke(Action a)
    {
        a.BeginInvoke(a.EndInvoke, null);
    }
}

Each Client contains a socket, so I can’t hardly Clone it.
The problem is, when I do the Invoke to c.WriteMessage, since the execution is delayed, it usually won’t fire on the first couple in the list, and will sometimes actually only fire a whole bunch on the very last item.

I know this has to do with c being a reference that changes before Invoke actually gets called, but is there a way to avoid this?

Doing a general for(int i=0 etc loop doesn’t seem to fix this issue.

Anyone have any ideas on how I can fix this?

Remember, can’t Clone Client.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T17:08:41+00:00Added an answer on May 28, 2026 at 5:08 pm

    Copy your c to local variable like this:

    lock (ClientLocker)
    {
        Trace.WriteLine("#WriteAll: " + sm.Header);
        foreach (Client c in Clients)
        {
            if (c.LoggedIn)
            {
                Client localC = c;
                Trace.WriteLine("#TryWriteTo[" + c.Id + "](" + sm.Header + ")");
                LazyAsync.Invoke(() => localC.WriteMessage(sm));
            }
        }
    }
    

    Do a web search for: “Access to modified closure” if you want to get more information.

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