Question

(Also posted here.)

So I have two tables, one is invalid table and the other is valid table.

valid table:

id
status
date

invalid table:

id
status
date

I have to produce a report with this output:

date       on-time  late  total  valid  invalid1  invalid2  total  rate
---------  -------  ----  -----  -----  --------  --------  -----  ----
9/10/2011  4        10    14     3      3         3         6   

• date: common fields on the 2 tables, field to group by, how many records on that day has
• on-time: count of all the id on the valid table
• late: count of all the records(id) on the invalid table
• total: total of on-time and late
• valid: count of id on the valid table with the “valid” status
• invalid1: count of id on the invalid table with “invalid1” status
• invalid2: count of id on the invalid table with “invalid2” status
• total: total of valid, invalid1, invalid2
• rate: average of totals

It’s basically multiple queries with different table. How can I achieve it?

Answer 1

Someting like this?

SELECT
    *,
    (result.total + result._total) / 2 AS rate
FROM (
    SELECT
        date,
        SUM(CASE WHEN data.valid = 1 THEN 1 ELSE 0 END) AS ontime,
        SUM(CASE WHEN data.valid = 0 THEN 1 ELSE 0 END) AS late,
        COUNT(*) AS total,
        SUM(CASE WHEN data.valid = 1 AND data.status = 'valid' THEN 1 ELSE 0 END) AS valid,
        SUM(CASE WHEN data.valid = 0 AND data.status = 'invalid1' THEN 1 ELSE 0 END) AS invalid1,
        SUM(CASE WHEN data.valid = 0 AND data.status = 'invalid2' THEN 1 ELSE 0 END) AS invalid2,
        SUM(CASE WHEN data.status IN ('valid', 'invalid', 'invalid2') THEN 1 ELSE 0 END) AS _total

    FROM (
        SELECT
            date,
            status,
            valid = 1
        FROM
            Valid
        UNION ALL
        SELECT
            date,
            status,
            valid = 0
        FROM
            InValid ) AS data
    GROUP BY
        date) AS result