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Asked: 2026-05-14T19:38:01+00:00

Am I fundamentally misunderstanding Ruby here? I’ve been writing Ruby code for about 2

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Am I fundamentally misunderstanding Ruby here? I’ve been writing Ruby code for about 2 years now and just today stumbled on this…

ruby-1.8.7-p249 > i = true and false
 => false 
ruby-1.8.7-p249 > i
 => true

Could somebody explain what’s going on here please? I’m sure it’s to spec, but it just seems counter intuitive to me…

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1 Answer

  1. Editorial Team

    The operators && and and have different precedence, and = happens to be in between.

    irb(main):006:0> i = true and false
=> false
irb(main):007:0> i
=> true
irb(main):008:0> i = true && false
=> false
irb(main):009:0> i
=> false
irb(main):010:0>

    The first is read as (i = true) and false, the second as i = (true && false).

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