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Home/ Questions/Q 6744231
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T12:03:32+00:00 2026-05-26T12:03:32+00:00

Am running this C program, but instead of answering The answer is 10, it

  • 0

Am running this C program, but instead of answering “The answer is 10”, it sends back the message: “The answer is 0”, even though it breaks at the right time.

Can you tell me what’s wrong?


#import <Foundation/Foundation.h>

int main (int argc, const char * argv[])
{
    int i;
    for(int i = 0; i < 12; i++){
        printf("Checking i = %d\n", i);
        if(i + 90 == i * i) {
            break;
        }
    }
    printf("The answer is %d.\n", i);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T12:03:33+00:00Added an answer on May 26, 2026 at 12:03 pm

    The problem is you have two i‘s.

    int main (int argc, const char * argv[])
    {
        int i; //Declares outer i
        for(int i = 0; i < 12; i++) //Declares a NEW i
        {
            printf("Checking i = %d\n", i);
            if(i + 90 == i * i) 
            {
                break;
            }
        }
        printf("The answer is %d.\n", i); //Uses the outer i
    }
    
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