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Home/ Questions/Q 409201
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T17:46:01+00:00 2026-05-12T17:46:01+00:00

Am working on my earlier hit count question and ran into another stumbling block:

  • 0

Am working on my earlier hit count question and ran into another stumbling block: how do I post an object’s model information through ajax ?

I am using the generic object_detail view for a number of my models and I want to add some ajax to the template that calls my updapte_object_hit_count function (thereby tracking the object’s hit count).

But since the data is passed via json/ajax, I’m not sure how I figure out which model/object I am working with exactly.

For example, what I would like to do (jQuery):

$(document).ready(function() {

    var data = {
        model : "{{ object.model }}", // this doesn't work, obviously
        pk    : "{{ object.pk }}",
        };

    $.post('{% url update_object_hit_count %}',data);

});

In my view, something clever like:

def update_object_hit_count(request):
    post = request.POST.copy() 
    model = post['model']
    obj = model.objects.get(pk=post['pk'])
    # more stuff using this obj

Any ideas on how to accomplish this? I thought I may be able to use ContentType but not sure how …

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  1. Editorial Team
    Editorial Team
    2026-05-12T17:46:01+00:00Added an answer on May 12, 2026 at 5:46 pm

    You could probably create a custom filter (django docs).

    Current Code Attempt (Community Wiki):

    from django import template
    
    register = template.Library()
    
    @register.filter
    def app_label(value):
        """Return an object's app_label"""
        try:
            return value._meta.app_label
        except:
            pass
    
    @register.filter
    def object_name(value):
        """Return an object's object_name"""
        try:
            return value._meta.object_name
        except:
            pass
    

    Then in your template:

    {% load ... %}
    
    {{ object|app_label }}
    {{ object|object_name }}
    

    The only other way I can think of would be adding a property to the model. This way means you don’t have to modify the model

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