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Editorial Team
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Asked: 2026-06-17T16:53:54+00:00

Amongst what I’m sure are a plethora of other problems, the $result variable isn’t

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Amongst what I’m sure are a plethora of other problems, the $result variable isn’t being recognized

getting a

Fatal error: Call to a member function fetch_assoc() on a non-object

and I’m not sure why. Any help would be appreciated. Here’s the code:

<html>
    <body>

        <?PHP

$db = new mysqli('localhost', 'root', '', 'edumacation');

if($db->connect_errno > 0){
    die('Unable to connect to database [' . $db->connect_error . ']');
}

$result = <<<SQL
    SELECT *
    FROM `student`
    WHERE `id` = 1
SQL;


while($row = 
        $result->fetch_assoc()){
    echo "<table border='1'><tr><th>Name</th><th>Grade</th><th>Favorite Teacher</th><th>Date Enrolled</th></tr>";
    echo "<tr><td>" . $row['first_name'] . "</td><td>" . $row['grade'] . "</td><td>" . $row['fav_teacher'] . "</td></tr>" . $row['enrolled'] . "<br />";
    echo "</table>";
}

?>
   </body> 
</html>
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1 Answer

  1. Editorial Team

    Well, you’re not actually executing the query, just setting a string to what you want the SQL to be. Something like this would work better;

    $sql = <<<SQL
  SELECT *
  FROM `student`
  WHERE `id` = 1
SQL;

if ($result = $db->query($sql)) {
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