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Asked: May 10, 20262026-05-10T19:22:28+00:00 2026-05-10T19:22:28+00:00

An XSLT-newbie problem: I need to substitute a text value in XML-file. All other

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An XSLT-newbie problem: I need to substitute a text value in XML-file. All other nodes must be left unchanged. Here’s my input file (in.xml):

<?xml version='1.0' encoding='UTF-8'?> <root>     <level1 attr1='val1'>         <level2>in</level2>     </level1> </root> 

Here’s my XSLT-transformation (subst.xsl):

<?xml version='1.0' encoding='UTF-8'?> <xsl:stylesheet version='1.0' xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>      <xsl:template match='/'>         <xsl:apply-templates />     </xsl:template>      <xsl:template match='//node()'>         <xsl:copy>             <xsl:apply-templates />         </xsl:copy>     </xsl:template>      <xsl:template match='/root/level1/level2/text()'>out</xsl:template> </xsl:stylesheet> 

I run it with the following Ant-script (build.xml):

<?xml version='1.0' encoding='UTF-8'?> <project name='test' default='test' basedir='.'>     <target name='test'>         <xslt style='subst.xsl' in='in.xml' out='out.xml' />     </target> </project> 

And here’s what I get (out.xml):

<?xml version='1.0' encoding='UTF-8'?><root>     <level1>         <level2>out</level2>     </level1> </root> 

Attribute ‘attr1’ of ‘level1’ is missing.

I would be very grateful if anyone

  • tell me what’s wrong with subst.xsl

OR

  • give me an idea how to force xslt-processor just copy non-matched nodes to output file and to do it by hand (which is in my case error-prone).
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  1. 2026-05-10T19:22:28+00:00Added an answer on May 10, 2026 at 7:22 pm

    Your identity transform is missing attributes (obviously). Use this instead:

    <xsl:stylesheet xmlns:xsl='http://www.w3.org/1999/XSL/Transform' version='1.0'>   <xsl:template match='@* | node()'>     <xsl:copy>       <xsl:apply-templates select='@* | node()'/>     </xsl:copy>   </xsl:template> </xsl:stylesheet> 

    Then, just add your last template.

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