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Home/ Questions/Q 592077
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T15:42:05+00:00 2026-05-13T15:42:05+00:00

And now after some work, I finally understand how the KDop bounding volume are

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And now after some work, I finally understand how the KDop bounding volume are created and how the collisions are intersected and I maked a working implementation of them.
Now the problem is another. 😀

How can I intersect (it has to be possible, or it would not make any sense) 2 K-Dop of different K values? (obviously we know beforehand which axis has been used to create those 2 K-Dop.)

Like how can i intersect a DOP6 (AABB) and a DOP14 (AABB + corners cut off)?
Or a DOP14 (AABB + corners cut off) and a DOP26 (AABB + Corners cut off + Edges cut off)?

The simple method (between KDOP with the same K) is

 public Boolean Intersects(kDOP a, kDOP b)
        {
            // TODO : How to do if the K is not the same?
            for (int i = 0; i < a.K / 2; i++)
                if ((a.Min[i] > b.Max[i]) || (a.Max[i] < b.Min[i]))
                    return false;
            return true;
        }

Another question is. How to do intersection between KDOP and say a Sphere? KDOP and a Capsule? KDOP and a OOB? KDOP and a AABB? (this should be easier if we know how to do with different K (as AABB is a DOP6 basically))
I mean what’s the common way to do intersection between these simple structures?

Thanks a lot for the answers!!!

EDIT : From some search on the net it seems that the separation axis is the way to go, but I can’t find any detailed information on how to implement it on the K-DOP. 😛

EDIT 2 : Someone has a working implementation of a separation axis theorem over KDOP? 😐

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T15:42:06+00:00Added an answer on May 13, 2026 at 3:42 pm

    If the Ks are a different order, just run your i loop to the minimum of a.K/2 or b.K/2.

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