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Home/ Questions/Q 4079488
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T17:48:31+00:00 2026-05-20T17:48:31+00:00

another list-dictionary question. I have a dict as follows with unit names and testnames

  • 0

another list-dictionary question.

I have a dict as follows with unit names and testnames in a list:

dictA = {('unit1', 'test1'): 10,  ('unit2', 'test1'): 78,  ('unit2', 'test2'): 2, ('unit1', 'test2'): 45}

units = ['unit1', 'unit2'] 
testnames = ['test1','test2']

How do we find the max of the values for each test in testnames:

I tried as follows:

def max(dict, testnames_array):
    maxdict = {}
    maxlist = []
    temp = []
    for testname in testnames_array:
        for (xunit, xtestname), value in dict.items():
            if xtestname == testname:
                if not isinstance(value, str):
                    temp.append(value)
            temp = filter(None, temp)
            stats = corestats.Stats(temp) 
            k = stats.max() #finds the max of a list using another module
            maxdict[testname] = k
    maxlist.append(maxdict)
    maxlist.insert(0,{'Type':'MAX'})
    return maxlist

Problem now is that im getting output:

[{'Type':'MAX'}, {'test1': xx}, {'test2':xx}]

where xx is all returned as a same values!!

where is my fault?
any simpler methods?
please advice. thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-20T17:48:31+00:00Added an answer on May 20, 2026 at 5:48 pm
    >>> dictA = {('unit1', 'test1'): 10,  ('unit2', 'test1'): 78,  ('unit2', 'test2'): 2, ('unit1', 'test2'): 45}
    >>> maxDict={}
    >>> for (unitName,testName),grade in dictA.items():
        maxDict[testName]=max(maxDict.get(testName,0),grade)
    
    
    >>> maxDict
    {'test1': 78, 'test2': 45}
    

    I guess this should solve it.

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