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Home/ Questions/Q 7501021
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T20:23:36+00:00 2026-05-29T20:23:36+00:00

answerFalse::Int->IO() answerFalse hp=do hp– if hp<=0 then putStrLn================Game Over================ else print(hp) i already declare

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answerFalse::Int->IO()
answerFalse hp=do
            hp--
            if hp<=0 then
                putStrLn"================Game Over================"

            else
                print(hp)

i already declare hp as int with value 3
now my problem is when i put “hp–“, it shows error

 Couldn't match expected type `IO a0' with actual type `Int'

but if i put “–hp”, the result print is 3 not 2.

i also tried let hp=hp-1, the system stuck there.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T20:23:42+00:00Added an answer on May 29, 2026 at 8:23 pm

    You can’t modify variables in Haskell. hp++ and ++hp (or hp-- and --hp) don’t work in Haskell at all; the reason why --hp compiles is that -- creates a comment which comments out the hp part.

    What you are trying to do is this:

    answerFalse hp =
      if hp - 1 <= 0
      then putStrLn "================Game Over================"
      else print hp
    

    You can also do it like this, by creating a new variable:

    answerFalse hp = do
      let newHp = hp - 1
      if newHp <= 0
        then putStrLn "================Game Over================"
        else print hp
    

    You need to review your basic Haskell knowledge by reading beginner tutorials. This question provides excellent resources for you.

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