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Home/ Questions/Q 7489601
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T15:16:50+00:00 2026-05-29T15:16:50+00:00

Answering to this question I stuck with this situation. Using reluctant match in my

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Answering to this question I stuck with this situation. Using reluctant match in my regex bring to this result

string s = Regex.Replace(".A.", "\\w*?", "B");

B.BAB.B

Why it doesn’t match and replace A?

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  1. Editorial Team
    Editorial Team
    2026-05-29T15:16:51+00:00Added an answer on May 29, 2026 at 3:16 pm

    Because the \\w*? matches as few \w as it possibly can, including 0 of them.

    Since you have \w* instead of \w+, the regex matches 0 or more \w.

    Since you have an additional ? on the \w*, the smallest possible match for this regex is the 0-length string, ”.

    Since the ? forces the regex to match as small a match as possible, it only ever matches 0-length strings. It can’t match a single character A because that would be a longer match than the shortest.

    Hence all 0-length strings in .A. (being: ''.''A''.'', where each possible 0-length string is marked as '') are replaced with a ‘B’, giving you ‘B.A.B’.

    If you want to disable this behaviour and replace at least one \w, you can use regex \w+?. However, by the same reasoning as before, the ? forces this to only ever replace \w of length one, so you may as well use regex \w.

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