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Home/ Questions/Q 6657689
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T01:48:03+00:00 2026-05-26T01:48:03+00:00

Any idea how to get test_trigger working? Create table test ( book_id Int UNSIGNED

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Any idea how to get test_trigger working?

Create table test (
    book_id Int UNSIGNED NOT NULL,
    book_views Int UNSIGNED NOT NULL DEFAULT 0,
Primary Key (book_id)) ENGINE = InnoDB;

Create table trigger_test (
    book_id Int UNSIGNED NOT NULL,
    book_views Int UNSIGNED NOT NULL DEFAULT 0,
Primary Key (book_id)) ENGINE = Memory;

delimiter $$
CREATE TRIGGER test_trigger
   AFTER UPDATE ON test
   FOR EACH ROW
   BEGIN
     DECLARE rows_count INT;
     SELECT count(1) FROM trigger_test WHERE book_id=NEW.book_id INTO @rows_count;

     IF @rows_count = 0 THEN
         INSERT INTO trigger_test(book_id, book_views)
         SELECT book_id, book_views FROM test where book_id = NEW.book_id;
     ELSE
         UPDATE trigger_test
         SET book_views = NEW.book_views
         WHERE book_id = NEW.book_id;
     END IF;
   END$$
delimiter ;

Insert/update is not working. Following code should insert row in trigger_test but its not inserting row.

insert into test values (1, 10);
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  1. Editorial Team
    Editorial Team
    2026-05-26T01:48:04+00:00Added an answer on May 26, 2026 at 1:48 am

    There is no need to reference the table ‘test’. Just use the NEW table like this

    INSERT INTO trigger_test(book_id,book_views)
    VALUES (NEW.book_id,NEW.book_views); 
    

    Also you could use the Replace statement.

    MySQL Replace Syntax

    REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted.

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