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Any smart way to convert a float like this:
float f = 711989.98f;
into a decimal (or double) without losing precision?
I’ve tried:
decimal d = (decimal)f;
decimal d1 = (decimal)(Math.Round(f,2));
decimal d2 = Convert.ToDecimal(f);
It’s too late, the 8th digit was lost in the compiler. The float type can store only 7 significant digits. You’ll have to rewrite the code, assigning to double or decimal will of course solve the problem.